How to calculate current motor value in single phase motor?
:1: There is an electric motor that used to drive conveyor machine. The electric motor has specifications: voltage is 200 Volt single phase, frequency is 50 Hz, cos phi is 0.82 and real power on the name plate is 330 Watt. How many current of electricity will flow into the motor?
:catat: Answer:
V = 200 Volt
f = 50 Hz
Cos phi = 0.82
P = 330 W
I = ...?
===================================
The formula of real power electricity in single phase motor
P = V I Cos phi . . . . . (Watt)
:pin: then
The formula of current electricity in single phase motor
I = P / (V Cos phi) . . . . . (Ampere)
====================================
I = 330 / (200 * 0.82)
I = 2 A.
:2: In the chocolate factory has an electric motor that has specifications: voltage is 220 Volt single phase, frequency is 50 Hz, cos phi is 0.78 and real power on the name plate is 2.2 kW. How many current of electricity will flow into the motor?
:catat: Answer:
V = 220 Volt
f = 50 Hz
Cos φ = 0.78
P = 2.2 kW → convert kW into W → 2.2 * 103 W = 2200 W
I = ...?
I = P / (V Cos φ)
I = 2200 / (220 * 0.78)
I = 12.82 A.
:3: The electric motor has specifications: voltage is 400 Volt single phase, frequency is 60 Hz, Cos φ is 0.85 Ampere and real power on the name plate is 6 HP. How many current of electricity will flow into the motor?
:catat: Answer:
V = 400 Volt
f = 60 Hz
Cos φ = 0.85
P = 6 HP → convert HP into W → 6 * 746 W = 4476 W
I = ...?
I = P / (V Cos φ)
I = 4476 / (400 * 0.85)
I = 13.165 A.
:catat: Answer:
V = 200 Volt
f = 50 Hz
Cos phi = 0.82
P = 330 W
I = ...?
===================================
The formula of real power electricity in single phase motor
P = V I Cos phi . . . . . (Watt)
:pin: then
The formula of current electricity in single phase motor
I = P / (V Cos phi) . . . . . (Ampere)
====================================
I = 330 / (200 * 0.82)
I = 2 A.
:2: In the chocolate factory has an electric motor that has specifications: voltage is 220 Volt single phase, frequency is 50 Hz, cos phi is 0.78 and real power on the name plate is 2.2 kW. How many current of electricity will flow into the motor?
:catat: Answer:
V = 220 Volt
f = 50 Hz
Cos φ = 0.78
P = 2.2 kW → convert kW into W → 2.2 * 103 W = 2200 W
I = ...?
I = P / (V Cos φ)
I = 2200 / (220 * 0.78)
I = 12.82 A.
:3: The electric motor has specifications: voltage is 400 Volt single phase, frequency is 60 Hz, Cos φ is 0.85 Ampere and real power on the name plate is 6 HP. How many current of electricity will flow into the motor?
:catat: Answer:
V = 400 Volt
f = 60 Hz
Cos φ = 0.85
P = 6 HP → convert HP into W → 6 * 746 W = 4476 W
I = ...?
I = P / (V Cos φ)
I = 4476 / (400 * 0.85)
I = 13.165 A.
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