headerphoto

An electric motor has specifications: voltage is 380 V, 3 phase, frequency is 50 Hz, 1500 rpm, cos phi is 0.8 and real power on the name plate is 22 kW. Convert to HP (Horse Power) and calculate, how many current of electricity will flow into the motor?
Connection of 3-Phase Motor

:catat: Answer:
1HP = 0.75 kW --> 22 kW / 0.75 kW x 1 HP = 29.33 HP
--> 22 kW ≈ 30 HP
:catat: The power of the motor is 30 HP

V = 380 V 3 fase
f = 50 Hz
Cos φ = 0.8
P = 22 kW = 22000 W
I = ...?

The formula of real power electricity in 3-phase:
P = √3 x V x I x Cos φ --> I = P / (√3 x V x Cos φ)
--> I = 22000 / (√3 x 380 x 0.8)
--> I = 41.78 A
:catat: The current of electricity will flow into the motor is 41,78 A

For reference, here is a table of the electric currents of a 3-phase motor, 380 V, cos phi 0.8

kWHPA
0.40.50.8
0.7511.4
1.11.52.1
1.522.8
2.234.2
345.7
3.757
4.568.5
5.57.510.4
7.51014.2
91217.1
111520.9
152028.5
18.52535.1
223041.8
304057
375070.3
456085.5
5575104.5
75100142.4

Read more »»
0 Comment Writer: 8:29 PM

This post is explain how to convert hexadecimal fractions to decimal numbers. As we known, hexadecimal number is system number who have 16 digit numbers, which is 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E and F, where:
A present of 10
B present of 11
C present of 12
D present of 13
E present of 14
F present of 15.
The picture below is show hexadecimal fraction to decimal, form 1st position to 5th position of the digit, before and after the hexadecimal point.
Hexadecimal fractions to decimal
Example 1:
Convert hexadecimal number 0.59A to decimal number

Completion:
0.59A (16) = ... (10)
1st digit after hexadecimal point: 5 → 5 × (1/ 161) = 5 × 0.0625 = 0.3125
2nd digit after hexadecimal point: 9 → 9 × (1/ 162) = 9 × 0.00390625 = 0.03515625
3rd digit after hexadecimal point: A → 10 × (1/ 163) = 10 × 0.000244141 = 0.00244141
sum all → 0.3125 + 0.03515625 + 0.00244141 = 0.35009766

0.59A (16) = 0.35009766 (10)

Example 2:
Convert hexadecimal number E2.81AC to decimal number

Completion:
E2.81AC (16) = ... (10)

before hexadecimal point
1st digit: 2 → 2 × 160 = 2 × 1 = 2
2nd digit: E → 14 × 161 = 14 × 16 = 224
sum all → 2 + 224 = 226

after hexadecimal point
1st digit: 8 → 8 × (1/ 161) = 8 × 0.0625 = 0.5
2nd digit: 1 → 1 × (1/ 162) = 1 × 0.00390625 = 0.00390625
3rd digit: A → 10 × (1/ 163) = 10 × 0.000244141 = 0.00244141
4th digit: C → 12 × (1/ 164) = 12 × 0.000015259 = 0.000183108
sum all → 0.5 + 0.00390625 + 0.00244141 + 0.000183108 = 0.506530768

E2.81AC (16) = 226.506530768 (10)

Read more »»
0 Comment Writer: 7:23 PM

This post is explain how to convert octal fractions to decimal numbers. The picture below is show octal fraction to decimal, form 1st position to 5th position of the digit, before and after the octal point.
Octal fractions to decimal
Example 1:
Convert Octal number 0.725 to decimal number

Completion:
0.725 (8) = ... (10)
1st digit after octal point: 7 → 7 × (1/ 81) = 7 × 0.125 = 0.875
2nd digit after octal point: 2 → 2 × (1/ 82) = 2 × 0.015625 = 0.03125
3rd digit after octal point: 5 → 5 × (1/ 83) = 5 × 0.001953125 = 0.009765625
sum all → 0.875 + 0.03125 + 0.009765625 = 0.916015625

0.725 (8) = 0.916015625 (10)

Example 2:
Convert octal number 105.2063 to decimal number

Completion:
105.2063 (8) = ... (10)

before octal point
1st digit: 5 → 5 × 80 = 5 × 1 = 5
2nd digit: 0 → 0 × 81 = 0 × 8 = 0
3rd digit: 1 → 1 × 82 = 1 × 64 = 64
sum all → 5 + 0 + 64 = 69

after octal point
1st digit: 2 → 2 × (1/ 81) = 2 × 0.125 = 0.25
2nd digit: 0 → 0 × (1/ 82) = 0 × 0.015625 = 0
3rd digit: 6 → 6 × (1/ 83) = 6 × 0.001953125 = 0.01171875
4th digit: 3 → 3 × (1/ 84) = 3 × 0.000244141 = 0.000732423
sum all → 0.25 + 0 + 0.01171875 + 0.000732423 = 0.262451173

501.2063 (8) = 69.262451173 (10)

Read more »»
0 Comment Writer: 9:06 AM

This post is explain how to convert binary fractions to decimal numbers. The picture below is show binary fraction to decimal, form 1st position to 5th position of the digit, before and after the binary point.
Binary fractions to decimal
Example 1:
Convert binary number 0.1101 to decimal number

Completion:
0.101 (2) = ... (10)
1st digit after binary point: 1 → 1 × (1/ 21) = 1 × 0.5 = 0.5
2nd digit after binary point: 0 → 0 × (1/ 22) = 0 × 0.25 = 0
3rd digit after binary point: 1 → 1 × (1/ 23) = 1 × 0.125 = 0.125
sum all → 0.5 + 0 + 0.125 = 0.625

0.101 (2) = 0.625 (10)

Example 2:
Convert binary number 1110.11011 to decimal number

Completion:
1110.11011 (2) = ... (10)

before binary point
1st digit: 0 → 1 × 20 = 0 × 1 = 0
2nd digit: 1 → 1 × 21 = 1 × 2 = 2
3rd digit: 1 → 1 × 22 = 1 × 4 = 4
4th digit: 1 → 1 × 23 = 1 × 8 = 8
sum all → 0 + 2 + 4 + 8 = 14

after binary point
1st digit: 1 → 1 × (1/ 21) = 1 × 0.5 = 0.5
2nd digit: 1 → 1 × (1/ 22) = 1 × 0.25 = 0.25
3rd digit: 0 → 0 × (1/ 23) = 0 × 0.125 = 0
4th digit: 1 → 1 × (1/ 24) = 1 × 0.0625 = 0.0625
5th digit: 1 → 1 × (1/ 25) = 1 × 0.03125 = 0.03125
sum all → 0.5 + 0.25 + 0 + 0.0625 + 0.03125 = 0.84375

1110.11011 (2) = 14.84375 (10)

Read more »»
0 Comment Writer: 3:50 PM

How to turn on the led of arduino, which is call the led pin?




At the picture above, the led pin is marked as L and to turn it on is very easy, just

upload the sketch

bellow. If you success to upload the code (sketch), the led pin will turn on for 1 second, then turn off for 1 second, and roll it over again and again.


/****************************************/
/* ARDUINO SKETCH (1): BLINK, FLIP-FLOP */
/* TURN ON THE LED AT PIN 13 */
/****************************************/

#define led 13

void setup(){
pinMode(led, OUTPUT);
}

void loop(){
digitalWrite(led, HIGH);
delay(1000);
digitalWrite(led, LOW);
delay(1000);
}


Read more »»
0 Comment Writer: 4:52 PM

We have four articles that used to calculate current, cos phi, HP and power of single phase motor. Now, we want to collect them, embrace the result of them, then rewrite them in this article, to be Data Sample of Single Phase Motor. I hope it will be usefull :hahaha:

Data Sample of Single Phase Motor

Voltage - Frequency - Power - Cos Phi - Current
110V - 60Hz - 272.25W - 0.75 - 3.3A
200V - 60Hz - 1500W - 0.79 - 9.5A
200V - 60Hz - 1865W - 0.8 - 11.656A
200V - 50Hz - 330W - 0.82 - 2A
220V - 50Hz - 200W - 0.733 - 1.24A
220V - 50Hz - 1200W - 0.83 - 6.572A
220V - 50Hz - 66W - 0.6 - 0.5A
220V - 50Hz - 2200W - 0.78 - 12.821A
400V - 70Hz - 2984W - 0.68 - 10.97A
400V - 70Hz - 2550W - 0.75 - 8.5A
400V - 70Hz - 2600W - 0.65 - 10A
400V - 60Hz - 4476W - 0.85 - 13.165A

The four articles that used to be data sample above are:
:1: How to calculate current motor value in single phase motor?
:2: How to calculate cos phi motor value in single phase motor?
:3: How to calculate power motor value in kW to HP?
:4: How to calculate power motor value in single phase motor?

Read more »»
0 Comment Writer: 11:28 AM

:1: There is an electric motor that used to drive conveyor machine. The electric motor has specifications: voltage is 200 Volt single phase, frequency is 50 Hz, cos phi is 0.82 and real power on the name plate is 330 Watt. How many current of electricity will flow into the motor?

:catat: Answer:
V = 200 Volt
f = 50 Hz
Cos phi = 0.82
P = 330 W
I = ...?

===================================
The formula of real power electricity in single phase motor
P = V I Cos phi . . . . . (Watt)

:pin: then

The formula of current electricity in single phase motor
I = P / (V Cos phi) . . . . . (Ampere)
====================================

I = 330 / (200 * 0.82)
I = 2 A.

:2: In the chocolate factory has an electric motor that has specifications: voltage is 220 Volt single phase, frequency is 50 Hz, cos phi is 0.78 and real power on the name plate is 2.2 kW. How many current of electricity will flow into the motor?

:catat: Answer:
V = 220 Volt
f = 50 Hz
Cos φ = 0.78
P = 2.2 kW → convert kW into W → 2.2 * 103 W = 2200 W
I = ...?

I = P / (V Cos φ)
I = 2200 / (220 * 0.78)
I = 12.82 A.

:3: The electric motor has specifications: voltage is 400 Volt single phase, frequency is 60 Hz, Cos φ is 0.85 Ampere and real power on the name plate is 6 HP. How many current of electricity will flow into the motor?

:catat: Answer:
V = 400 Volt
f = 60 Hz
Cos φ = 0.85
P = 6 HP → convert HP into W → 6 * 746 W = 4476 W
I = ...?

I = P / (V Cos φ)
I = 4476 / (400 * 0.85)
I = 13.165 A.

Read more »»
0 Comment Writer: 5:30 AM

:1: We have an electric motor that used to drive washing machine. The electric motor has specifications: voltage is 220 Volt single phase, frequency is 50 Hz, current of electricity is 1.24 Ampere and real power on the name plate is 200 Watt. How many cos phi of electricity of the motor?

:catat: Answer:
V = 220 Volt
f = 50 Hz
I = 1.24 A
P = 200 W
Cos phi = ...?

===================================
The formula of real power electricity in single phase motor
P = V I Cos phi . . . . . (Watt)

then

The formula of cos phi in single phase motor
Cos phi = P / (V I)
or
Cos φ = P / (V I)
====================================

Cos phi = 200 / (220 * 1.24)
Cos phi = 0.733.

:2: In the paper bag factory has an electric motor that has specifications: voltage is 200 Volt single phase, frequency is 60 Hz, current of electricity is 9.5 Ampere and real power on the name plate is 1.5 kW. How many cos φ of electricity of the motor?

:catat: Answer:
V = 200 Volt
f = 60 Hz
I = 9.5 A
P = 1.5 kW → convert kW into W → 1.5 * 103 W = 1500 W
Cos φ = ...?

Cos φ = P / (V I)
Cos φ = 1500 / (200 * 9.5)
Cos φ = 0.79.

:3: The electric motor has specifications: voltage is 400 Volt single phase, frequency is 70 Hz, current of electricity is 10.97 Ampere and real power on the name plate is 4 HP. How many cos φ of electricity of the motor?

:catat: Answer:
V = 400 Volt
f = 70 Hz
I = 10.97 A
P = 4 HP → convert HP into W → 4 * 746 W = 2984 W
Cos φ = ...?

Cos φ = P / (V I)
Cos φ = 2984 / (400 * 10.97)
Cos φ = 0.68.

Read more »»
0 Comment Writer: 5:00 AM

:1: There is an electric motor that used to drive water pump machine. The electric motor has specification: voltage 220 Volt single phase, frequency 50 Hz, current 9 Ampere and power 1.2 kW. How many horse power or HP power of electricity that used the motor?

:catat: Answer:
V = 220 Volt
f = 50 Hz
I = 9 A
P = 1.2 kW
P = ...? HP

====================================
The conversion formula of kW to HP
1 kW = 1/ 0.746 HP
=====================================

P = 1.2 / 0.746 HP
P = 1.61 HP.

:2: In the workshop has an electric motor that has specification: voltage 200 Volt single phase, frequency 60 Hz, and power 2.5 HP. How many kilo Watt power of electricity that used the motor?

:catat: Answer:
V = 200 Volt
f = 60 Hz
P = 2.5 HP
P = ...? kW

====================================
The conversion formula of HP to kW
1 HP = 0.746 kW
=====================================

P = 2.5 * 0.746 kW
P = 1.865 kW.

:3: The electric motor has specification: voltage 400 Volt single phase, frequency 70 Hz, current 8.5 Ampere and cos phi 0.75. How many horse power or HP power of electricity that used the motor?

:catat: Answer:
V = 400 Volt
f = 70 Hz
I = 8.5 A
Cos phi = 0.75
P = ...? HP

P = V I Cos phi
P = 400 * 8.5 * 0.75
P = 2550 Watt
P = 2.55 kW
P = 3.418 HP.

Read more »»
0 Comment Writer: 9:45 AM

:1: We have an electric motor that used to drive fan machine. The electric motor has specification: voltage 220 Volt single phase, frequency 50 Hz, current 0.5 Ampere and cos phi 0.6. How many power of electric that used the motor?


:catat: Answer:
V = 220 Volt
f = 50 Hz
I = 0.5 A
Cos phi = 0.6
P = ... ?

P = V I Cos phi
P = 220 * 0.5 * 0.6
P = 66 Watt.

:2: The electric motor has specification: voltage 110 Volt single phase, frequency 60 Hz, current 3.3 Ampere and cos phi 0.75. How many power of electric that used the motor?

:catat: Answer:
V = 110 Volt
f = 60 Hz
I = 3.3 A
Cos phi = 0.75
P = ... ?

P = V I Cos phi
P = 110 * 3.3 * 0.75
P = 272.25 Watt.

:3: The electric motor has specification: voltage 400 Volt single phase, frequency 70 Hz, current 10 Ampere and cos phi 0.65. How many kilo Watt power of electric that used the motor?

:catat: Answer:
V = 400 Volt
f = 70 Hz
I = 10 A
Cos phi = 0.65
P = ... ?

P = V I Cos phi
P = 400 * 10 * 0.65
P = 2600 Watt
P = 2.6 kW.

Read more »»
0 Comment Writer: 6:00 PM
Previous
Subscribe to: Posts (Atom)